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alexandr1967 [171]
3 years ago
10

an item is priced 20 percent more than its wholesale cost of the wholesale cost was 800 what is the price of the item?

SAT
1 answer:
Fittoniya [83]3 years ago
6 0
Since the price is 20% (0.2)  more that means that it is 120% (1.20) of the original value.
Multiplying 1.20 with 800 gets you 960
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the reduction of carbon dioxide emissions poses few threats to sustaining economic growth in developing countries.
Oksi-84 [34.3K]

It is false that the reduction of carbon dioxide emissions poses few threats to sustaining economic growth in developing countries.

Given that the reduction of carbon dioxide emissions poses few threats to sustaining economic growth in developing countries.

We are required to say whether the statement is true or false.

Economic growth basically defined as the increase or improvement in the inflation-adjusted market value of the goods and services produced by an economy over a certain period of time.

The reduction of carbon dioxide emissions does not poses threats but benefits our country and in result lead to increase in economic growth of the countries.

Hence it is false that the reduction of carbon dioxide emissions poses few threats to sustaining economic growth in developing countries.

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What the quarities of good supplier in the market should have?​
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1. Remains compliant with industry standards. Ultimately, buyers need to know that suppliers aren't going to add extra risk to their organisations' risk profiles.

2. Keeps information up-to-date.

3. Strives to continually improve.

4. Demonstrates innovation.

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For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
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The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

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