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3 years ago

EASY 20 points! Please Solve this Algebra 1 question.

Mathematics

2 answers:

Andrei [34K]3 years ago

5 0

Let W = width of the pool

area of back yard = (3W +5)^2

area of pool = W(W+10)

area around pool = (3W+5)^2 - W(W+10)

enyata [817]3 years ago

4 0

length of pool, L = 10 + W
width of pool, W

pool area = W(10+W)

backyard is square shaped.. sides are equal
backyard side length, S = 5 + 3W

Area backyard = (5+3W)(5+3W)
subtract pool area

Area surrounding pool
= (5+3W)(5+3W) - W(10+W)
simplify the expression, foil
= 25 + 30W + 9W^2 - 10W - W^2
combine like terms
A = 8W^2 + 20W + 25

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Answer:

Step-by-step explanation:

Let first odd number = a, second odd number = a +2, third odd number = a + 4

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Second odd number = a + 2 = 329

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Answer:

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Setting up the diagram that describes the given scenario, we would end up with a right-angled triangle as the one shown in the attached image

where:

height of the balloon = 4 km represents one side of the triangle

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distance between the balloon and the station is the length we want to find and it represents the hypotenuse of the triangle.

To get the length of the hypotenuse, we will use the Pythagorean theorem

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Substitute with the givens:

$hypotenuse = +\sqrt{(4)^2 + (1)^2}$ = √17 ≈ 4.1 km

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