Question

EASY 20 points! Please Solve this Algebra 1 question.

Answer 1

Let W = width of the pool

area of back yard = (3W +5)^2

 area of pool = W(W+10)

 area around pool = (3W+5)^2 - W(W+10)

Answer 2

length of pool, L = 10 + W
width of pool, W

pool area = W(10+W)

backyard is square shaped.. sides are equal
backyard side length, S = 5 + 3W

Area backyard = (5+3W)(5+3W)
subtract pool area

Area surrounding pool
= (5+3W)(5+3W) - W(10+W)
simplify the expression, foil
= 25 + 30W + 9W^2 - 10W - W^2
combine like terms
A = 8W^2 + 20W + 25