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4 years ago

How do I write decimal into a fraction

2 answers:

8 0

There is 3 steps

Step 1: Write down the decimal divided by 1, like this: decimal 1.
Step 2: Multiply both top and bottom by 10 for every number after the decimal point. ...
Step 3: Simplify (or reduce) the fraction.

that's all folks

MrMuchimi4 years ago

8 0

EXAMPLE:

Write down the decimal divided by 1, like this: decimal 1. Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.) Step 3: Simplify (or reduce) the fraction.

This might help you

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The percentage of questions she got correct is 88%

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3 years ago

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4 years ago

The absolute value of -1/4 is

abruzzese [7]

Answer: 1/4

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4 years ago

After swimming 50 feet below the surface of the water, a

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20, c

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7 0

3 years ago

3. Suppose the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 custo

stich3 [128]

Answer:

The probability that the average number of customers in the sample is between 290 and 310 is 0.61922.

Step-by-step explanation:

We are given that the local Best Buy store averages 301 customers every day entering the facility with a standard deviation of 80 customers.

A random sample of 50 business days was selected.

Let $\bar X$ = sample average number of customers

The z-score probability distribution for sample average is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population average = 301 customers

$\sigma$ = population standard deviation = 80 customers

n = sample of business days = 50

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

(a) Probability the average number of customers in the sample is between 290 and 310 is given by = P(290 < $\bar X$ < 310) = P( $\bar X$ < 310) - P( $\bar X$ $\leq$ 290)

P( $\bar X$ < 310) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{310-301}{\frac{80}{\sqrt{50} } }$ ) = P(Z < 0.79) = 0.78524

P( $\bar X$ $\leq$ 290) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{290-301}{\frac{80}{\sqrt{50} } }$ ) = P(Z $\leq$ -0.97) = 1 - P(Z < 0.97)

= 1 - 0.83398 = 0.16602

{Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.79 and x = 0.97 in the z table which has an area of 0.78524 and 0.83398 respectively.}

Therefore, P(290 < $\bar X$ < 310) = 0.78524 - 0.16602 = 0.61922

Hence, the probability that the average number of customers in the sample is between 290 and 310 is 0.61922.

4 0

3 years ago