11th term is 10240
Step-by-step explanation:
- Step 1: Given the sequence 10,20,40. So a(1) = 10, common ration, r = 20/10 = 2 Find the 11th term using the nth term formula, a(n) = ar^n-1
⇒ a(11) = 10 × 2^10 = 10 × 1024 = 10240
Answer:1.36 for the chips
Step-by-step explanation:
15-9.99=5.01
5.01-3.65=1.36
Answer:
95%
Step-by-step explanation:
The Empirical rule, also the 68–95–99.7 rule, states that for a population that is approximately normal or symmetrical, nearly all of the data values will lie within three standard deviations of the mean;
68% of data values will fall within one standard deviation from the mean
95% of data values will fall within two standard deviation from the mean
99.7% of data values will fall within three standard deviation from the mean
From the graph given, we note that the weights 60 and 80 pounds fall within two standard deviations from the mean;
70 ± (2*5) = 70 ± 10 = (60, 80)
70 is the mean, 5 the standard deviation and 2 the number of standard deviations from the mean. From the Empirical rule we can conclude that the probability that a boxer weighs between 60 and 80 pounds is 95%
Answer:100$-100% 100*12.5=1250
1250/100=12.5
?-12.5%
Step-by-step explanation:
Answer:
thats helpful
Step-by-step explanation:
