m∠HDG = 28°, m∠EFG = 50°, m∠DEG = 67°, m∠DGE = 65°
Solution:
Triangle sum property:
Sum of the angles of the triangle = 180°
In ΔDHG,
m∠HDG + 120° + 32° = 180°
m∠HDG + 152° = 180°
m∠HDG = 180° – 152°
m∠HDG = 28°
In ΔGEF,
m∠EFG + 17° + 113° = 180°
m∠EFG + 130° = 180°
m∠EFG = 180° – 130°
m∠EFG = 50°
Sum of the adjacent angles in a straight line is 180°
m∠DEG + m∠DEF = 180°
m∠DEG + 113° = 180°
m∠DEG = 180° – 113°
m∠DEG = 67°
In ΔDGE,
m∠DGE + 48° + 67° = 180°
m∠DGE + 115° = 180°
m∠DGE = 180° – 115°
m∠DGE = 65°
Hence m∠HDG = 28°, m∠EFG = 50°, m∠DEG = 67°, m∠DGE = 65°.
Answer:
• Group the h terms by organised term arrangement :
• Then using distributive property, factorise out the value h so that the reverse is true.
• for the variable "lw", divide it by h in order to add it to the bracket of (w + l). Make sure the reverse is true:
• finally, completely factorise out the value h
1/8 vanilla, 3/8 almonds, 1/2 pineapple.....ratio : 1/8,3/8,1/2
bottle 1 bottle 2 bottle 3
vanilla : 1 2 1 1/2
almond : 3 6 4 1/2
pineapple : 4 8 6
