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Elina [12.6K]
3 years ago
6

2/3 of the product of 3/8 and 16

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0
2/3(3/8x16). 2/3(6). 4. The answer is 4 :)
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A quarter back is sacked for a loss of 5 yards. On the next play, his team loses 15 yards. Then the team gains 12 yards on the t
Romashka [77]

The final amount of yards the team has is 8 yards.

5 0
3 years ago
The ages of the people in attendance at the showing of an award-winning foreign film are shown below.
guapka [62]

Definition: A histogram visualises the distribution of data over a continuous interval or certain time period. Each bar in a histogram represents the tabulated frequency at each interval.

According to the given histogram,

0-20 years occur 15 times,

21-40 years occur 40 times,

41-60 years occur 40 times,

61-80 years occur 15 times.

This shows that the data is symmetrical and the majority of the attendees were between the ages of 21 and 60 (40 times).

Answer: correct choice is B.

5 0
3 years ago
Read 2 more answers
A. The length side b equals the length of side c
Ann [662]
Shiii it could be answer c
3 0
3 years ago
Mr. Akika has 49 21 cent and 31 cent stamps all told. The stamps are worth $13.39. how many of each kind of stamps does he have?
Lana71 [14]

Mr Akika has 18  21-cent stamp and 31 31-cent stamp.  

He has 49 21-cent and 31-cent stamps all told.

let

x = number of 21 cent stamp

y = number of 31 cent stamp

Therefore,

<h3>Total number of stamp:</h3>
  • x + y  = 49
<h3>Total cost of stamp:</h3>
  • 21x + 31y = 1339

Therefore,

x + y = 49

21x + 31y = 1339

21x + 21y = 1029

10y = 310

y = 310 / 10

y = 31

Therefore,

x = 49 - 31

x = 18

Therefore, Mr Akika has 18  21-cent stamp and 31 31-cent stamp.  

learn more on system of equation: brainly.com/question/1369852?referrer=searchResults

4 0
2 years ago
please help me evaluate this. the answer is B but im not sure how to get the answer without using a calculator. please show step
iragen [17]

Answer:

  b.  9/100

Step-by-step explanation:

It helps if you have memorized the cubes of small integers. Of course, the ones needed here are ...

  3³ = 27

  10³ = 1000

The desired value can be simplified to ...

  \left(-\dfrac{1000}{27}\right)^{-2/3}=\left(-\sqrt[3]{\dfrac{3^3}{10^3}}\right)^2=\dfrac{(-3)^2}{10^2}=\dfrac{9}{100}

6 0
3 years ago
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