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3 years ago

Solve 7x/4 = -6 Please with work shown thank you

1 answer:

4 0

Let's solve your equation step-by-step.

7x4=−6

Step 1: Simplify both sides of the equation.

74x=−6

Step 2: Multiply both sides by 4/7.

(47)*(74x)=(47)*(−6)

x=−247

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How many regions can be found at the left side of the normal distribution curve?

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Step-by-step explanation:

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3 years ago

Which of the following is a solution to the equation 0=x^2-8x-13

adoni [48]

I would say "c".
Two solutions were found :
x =(8-√116)/2=4-√ 29 = -1.385
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3 years ago

I really need help guys can some one plz help me it's for 10 points

11111nata11111 [884]

Answer:

$\sqrt{8}----- 2units,2units$

$\sqrt{7} ------\sqrt{5}units,\sqrt{2}units$

$\sqrt{5}-------1unit,2units$

$3------2units, \sqrt{5}units$

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

$Formula: c^2=a^2+b^2$

1. $a=\sqrt{5}, b=\sqrt{2}$

Plug this into the formula.

$c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }$

The square here eliminates the roots.

$c=\sqrt{5+2}\\ c=\sqrt{7}$

2. $a=\sqrt{3}, b=4$

$c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}$

3. $a=2, b=\sqrt{5}$

$c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3$

4. $a=2, b=2$

$c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}$

5. $a=1, b=2$

$c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}$

7 0

3 years ago

Round 325.49 to the nearest tenth place

Travka [436]

Random letters so i can just put the answer

325.50 i think

3 0

3 years ago

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SIZIF [17.4K]

Answer:

i got you fam

Step-by-step explanation:

see ya

6 0

3 years ago