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Kaylis [27]
3 years ago
6

Taneisha's family has signed up for a new cell phone plan. Taneisha now has a limit on the number of texts she can send or recei

ve each month. She can text no more than 300 times per month.
1. What's is the least number of texts she can make in a month?
2.write an inequality to represent the statement. Use n for the number off texts.
3.what's is the greatest number of text she can make in a month.
4.write an inequality to represent the statement.Use n for the number of texts.
5.write the statement from parts(b) and(d) as a compound inequity.
6.write the compound inequality in compact from.
Mathematics
1 answer:
anyanavicka [17]3 years ago
4 0
<span>1 and 2. Taneisha can send as few as 0 texts, or n>=0.
   
3 and 4. Taneisha can send as many as 300 texts in a month, or n<=300.
   
5. In this case, n>=0 and n<=300.
   
6. Putting these in compound form to make them one statement gives 0 <= n <= 300.</span>
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3/4(8x-4)=7x+2 This is a linear equation please help!
aleksandrvk [35]

Simplify the left hand side by multiplying the terms in the parenthesis by 3/4, i.e. divide them by 4 and multiply them by 3:

\dfrac{3}{4}(8x-4)=7x+2 \iff 3(2x-1)=7x+2 \iff 6x-3 = 7x+2

Subtract 6x from both sides:

-3=x+2

Subtract 2 to both sides:

x=-5

4 0
3 years ago
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What is a fraction close to but greater than 1
Nesterboy [21]
100/99 is one, there are infinite answers though
7 0
3 years ago
A buoy floating in the sea is bobbing in simple harmonic motion with period 2 seconds and amplitude 8 in. Its displacement d fro
Mrac [35]

Answer:

The equation of the displacement d as a function of time t is :

d(t)=8sin(\pi t+\pi )

Step-by-step explanation:

Generally , A simple harmonic wave is a sinusoidal function that is it can be expressed in simple sin or cos terms.

Thus,

d(t) = Asin(wt+c)

is the general form of displacement of a SHM.

where,

  • <em>d(t) is the displacement with respect to the mean position at any time t</em>
  • <em>A is amplitude </em>
  • <em>w is the natural frequency of oscillation (rads^{-1})</em>
  • <em>c is the phase angle which indicates the initial position of the object in SHM (rad)</em>

given,

  1. Time period (T) = 2s
  2. A=8
  3. The natural frequency (w) and time period (T) is :

                               w=\frac{2\pi} {T}

∴

w = \frac{2\pi }{2}  = \pi rads^{-1}

∴

the equation :

<em>⇒d(t)=8sin(\pi t+c)    </em>                    ------1

since d=0 when t=o ,

<em>⇒0=8sinc\\c=n\pi                         ------2</em>

where n is an integer ;

<u>⇒since the bouy immediately moves in the negative direction , x must be negative or c must be an odd multiple of \pi.</u>

<em>⇒ d(t) = 8sin(\pi t+(2k+1)\pi )         ------3</em>

where k is also an integer ;

the least value of k=0;

thus ,

the equation is :

d(t)=8sin(\pi t+\pi )

<em></em>

7 0
3 years ago
WILL GIVE BRAINLIEST
scoray [572]
Inverse Variation is shown through the formula y=k/x
plug in the given values and solve for k: 3=k/5 so k=15

Answer: y=15/x
4 0
3 years ago
More math help please!
Nata [24]
AS we know that:

V=SA*h

And we have the volume and we can calculate the SA,,,

So that, we can conclude:
h= \frac{V}{SA} = \frac{323.5}{\pi (7)^2} =2.1015~~in

Are you satisfied?




3 0
3 years ago
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