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tatuchka [14]
3 years ago
9

Determine the length of x and y. Round your answer to the nearest tenth, if necessary.

Mathematics
2 answers:
Marat540 [252]3 years ago
8 0
X=EF Y=DF thats what i think it is
Alona [7]3 years ago
7 0

Answer:

x= EF  and y= DF

Step-by-step explanation:

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The weight of a dog crate is 5.6 lbs. the crate and 3 puppies together weigh 36.35 lbs. estimate the weight of one puppy.
nata0808 [166]
36.35 - 5.6 = 30.75 ÷ 3 = 10.25

7 0
3 years ago
How do I solve this equation using long polynomial division?
gulaghasi [49]
Oh okie oh gosh lol lol I don’t know
8 0
3 years ago
A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po
Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call h the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is h - 49.

The wire length d is 14 ft longer than height h, hence

d= h+14.

Thus we get a right triangle with hypotenuse d= y+14, perpendicular  h, and base h-49; therefore, the Pythagorean theorem gives

(h-49)^2+h^2 = (h+14)^2

which upon expanding we get:

h^2-98h+2401 = h^2+28h+196

further simplification gives

h^2-126h+2205=0,

which is a quadratic equation with solutions

h =21ft\\h = 105ft.

Since the first solution h =21ft will give the triangle base length of 21ft-49ft = -28ft which is negative; therefore, we disregard it and pick the solution h = 105ft.

Hence, the height of the pole is 105ft.

3 0
3 years ago
Write the standard form equation of the ellipse shown in the graph, and identify the foci.
vlada-n [284]

Answer option A

From the given graph is a Vertical ellipse

Center of ellipse = (-2,-3)

Vertices are (-2,3)  and (-2,-9)

Co vertices are (-6,-3) and (2,-3)

The distance between center and vertices = 6, so a= 6

The distance between center and covertices = 4 , so b= 4

The general equation of vertical ellipse is

\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2}=1

(h,k) is the center

we know center is (-2,-3)

h= -2, k = -3 , a= 6  and b = 4

The standard equation  becomes

\frac{(x+2)^2}{4^2} + \frac{(y+3)^2}{6^2}=1

\frac{(x+2)^2}{16} + \frac{(y+3)^2}{36}=1

Foci  are (h,k+c)  and (h,k-c)

c=\sqrt{a^2-b^2}

Plug in the a=6  and b=4

c=\sqrt{6^2-4^2}

 c=\sqrt{20}

  c=2\sqrt{5}, we know h=-2  and k=-3

Foci  are   (-2,-3+2\sqrt{5})  and  (-2,-3-2\sqrt{5})

Option A is correct

6 0
3 years ago
Jordan is making a beaded necklace two thirds of the beads she uses are red and 4/21 of the beads are blue she wants the rest to
stiks02 [169]

Answer:

2/3= 14/21....red beads...4/21 blue beads...14+4= 18/21...so you need 3/21 more to finish the necklace and 3/21=1/7 in white beads

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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