All categories

3 years ago

What is the answer?????

Mathematics

1 answer:

KiRa [710]3 years ago

8 0

Answer:

x = 9

Step-by-step explanation:

2 sides are 4 less than x, that is x - 4

The perimeter is the sum of all 3 sides, thus

x + x - 4 + x - 4 = 19, that is

3x - 8 = 19 ( add 8 to both sides )

3x = 27 ( divide both sides by 3 )

x = 9

You might be interested in

Find the values of a and b such that x² + 2x - 7 = ( x + a )² + b

gizmo_the_mogwai [7]

Answer:

a = 1 ; b = - 8

Step-by-step explanation:

x² + 2x - 7 = (x² + 2x + 1) - 1 - 7 = (x + 1)² - 8

a = 1 

b = - 8

8 0

3 years ago

Read 2 more answers

1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago

Help me with this!! Will mark Brainliest

ollegr [7]

Answer:

yes both are the distance of 99mm

3 0

4 years ago

Read 2 more answers

With a ruler, Diamond determines the diameter of a golf ball to be 4.2 centimeters (a radius of 2.1 cm) and the diameter of a pr

Troyanec [42]

Answer:

Diamonds is incorrect, because, the volume of the softball is 8 times the volume of the golf ball

Step-by-step explanation:

we know that

The volume of a sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

where

r is the radius

step 1

Find the volume of the golf ball

we have

$r=2.1\ cm\\pi =3.14$

substitute

$V=\frac{4}{3}(3.14)(2.1)^{3}=38.77\ cm^3$

step 2

Find the volume of the the softball

we have

$r=4.2\ cm\\pi =3.14$

substitute

$V=\frac{4}{3}(3.14)(4.2)^{3}=310.18\ cm^3$

step 3

Find the ratio of volumes

Divide the volume of the softball by the volume of the golf ball

$\frac{310.18}{38.77}=8$

That means

Diamonds is incorrect, because, the volume of the softball is 8 times the volume of the golf ball

7 0

3 years ago

Bob fenced in his backyard. The perimeter of the yard is 22 feet, and the length of his yard is 5 feet. Use the perimeter formul

brilliants [131]

<h2>Answer: C. 72 in.</h2>

Step-by-step explanation:

Since the perimeter is 22, take out 10, or (5 × 2) to get 12
Now divide 12 by 2 to get 6.
Since the answer is in inches, multiply by 12 to get 72 inches.

Proof:

P = 2L + 2W

22 = 2(5) + 2(6)

22 = 10 + 12

22 = 22

8 0

4 years ago

Read 2 more answers