Answer: Last Option

Step-by-step explanation:
The initial height of the plant of species A is 25 cm and grows 3 centimeters per month.
If m represents the number of months elapsed then the equation for the height of the plant of species A is:

For species B the initial height is 10 cm and it grows 8 cm each month
If m represents the number of months elapsed then the equation for the height of the plant of species B is:

Finally, the system of equations is:

The answer is the last option
It would be a parallelogram
Answer:
2n - 11
Step-by-step explanation:
Note there is a common difference d between consecutive terms of the sequence, that is
d = - 7 - (- 9) = - 5 - (- 7) = - 7 + 9 = - 5 + 7 = 2
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 9 and d = 2, thus
= - 9 + 2(n - 1) = - 9 + 2n - 2 = 2n - 11
You can get a 5 this many ways.
2 + 3
3 + 2
1 + 4
4 + 1
That number is 4
the total number of ways you can throw two cubes is 6 * 6 ways.
Of those ways 4 are successful
4/36 = 1/9 <<<< Answer.
B <<<< answer
Answer:

Step-by-step explanation:
Slant Height = 10 cm
Base Edge = 12 cm
<u>Finding the Height using Pythagorean Theorem:</u>
![\sf c^2 = a^2 + b^2 \\\\Where \ c = 10\ cm , b = 6\ cm [Half of 12] \ and \ a \ is \ height\\\\10^2 = a^2 + 6^2\\\\100=a^2 +36\\\\100-36 = a^2\\\\64 = a^2\\\\Taking \ sqrt \ on \ both \ sides\\\\Height= 8 \ cm](https://tex.z-dn.net/?f=%5Csf%20c%5E2%20%3D%20a%5E2%20%2B%20b%5E2%20%5C%5C%5C%5CWhere%20%5C%20c%20%3D%2010%5C%20cm%20%2C%20b%20%3D%206%5C%20cm%20%5BHalf%20of%2012%5D%20%5C%20and%20%5C%20a%20%5C%20is%20%5C%20height%5C%5C%5C%5C10%5E2%20%3D%20a%5E2%20%2B%206%5E2%5C%5C%5C%5C100%3Da%5E2%20%2B36%5C%5C%5C%5C100-36%20%3D%20a%5E2%5C%5C%5C%5C64%20%3D%20a%5E2%5C%5C%5C%5CTaking%20%5C%20sqrt%20%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5CHeight%3D%208%20%5C%20cm)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
<u>Now, Finding the volume:</u>

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>