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rodikova [14]
3 years ago
8

In the figure below, ∆ABC is similar to ∆DBE. Given that BE=10cm, AB=3cm and BD=4cm. Find the length of BC.

Mathematics
1 answer:
frez [133]3 years ago
3 0
Check the picture below

solve for CB

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68.76 rounded to the nearest whole number
Ahat [919]
68,76 rounded to the nearest whole number will be equal 69 

hope this will help you 
7 0
3 years ago
If 't' bags of chips cost $c, what is the cost of 5 bags of chips?
allsm [11]

Answer:

$ (C/t ) × 5

= $ 5C/t

.....................................

4 0
1 year ago
The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

 

:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

         Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

   the lower set of data=

  1901   1902    1908   1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

 

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920   1925   1928   1929   1930   1932   1933   1935  

Minimum value= 1920

Maximum value= 1935

Range=  15 (  1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920   1925   1928   1929  

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930   1932   1933   1935  

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0
3 years ago
What are the dimensions of the product?
Oksi-84 [34.3K]

Answer:

<h2>2 x 2</h2>

Step-by-step explanation:

Dimensions: m x n

m = number of rows

n = number of columns

When multiplying two matrices:

m x n *  n x k = m x k

MATIX 1:

m = number of rows

n = number of columns

MATRIX 2:

n = number of rows

k = number of columns

RESULTING MATIX:

m = number of rows

k = number of columns

2 x 3 * 3 x 2 = 2 x 2

8 0
3 years ago
Read 2 more answers
Ryan also found that he could model the height of his plant with the equation h = 0.5d + 4, where d is the number of days and h
shusha [124]

Answer:

{4, 4.5, 5, 5.5, 6, 6.5, 7} {0, 1, 2, 3, 4, 5, 6}. 4 ≤ h ≤ 7 0 ≤ d ≤ 6. 4 ≤ d ≤ 7. {4, 5, 6, 7}. 0 ≤ h ≤ 6 0 ≤ h ≤ 7

4 0
2 years ago
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