Question

(PLEASE HELP) Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Write an inequality that would be used to solve for the least amount of money he needs to deposit to avoid a fee.
A. 727.29 + 248.50 − x ≥ 500
B. 727.29 + 248.50 − x ≤ 500
C. 727.29 − 248.50 + x ≥ 500
D. 727.29 − 248.50 − x ≤ 500

Answer 1

Let x represent amount of money that Tony needs to deposit to avoid a fee.

We have been given that Tony has $727.29 in his checking account. He wrote a check for $248.50 today.

Let us find amount of money left in Tony's account after writing a check of $248.50 as:

$\ 727.29-\ 248.50$

After depositing x dollars in account, total amount of money in Tony's account would be $727.29-248.50+x$.

Since Tony must maintain a $500 balance to avoid a fee, so amount of money is his account should be greater than or equal to 500.

We can represent this information in an inequality as:

$727.29-248.50+x\geq 500$

Therefore, our required inequality would be $727.29-248.50+x\geq 500$ and option C is the correct choice.

Let us solve for x.

$478.79+x\geq 500$

$478.79-478.79+x\geq 500-478.79$

$x\geq 21.21$

Therefore, Tony must deposit at-least $21.21 to avoid a fee.