83 1/3% = (83 1/3)/100
= ((3*83 + 1)/3)/100
<span> = (250/3)/100 </span>
<span> = 250/300 </span>
= (5*50)/(6*50) = (5/6)*(50/50)
<span>83 1/3% = 5/6</span>
Answer:
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

You have been asked to calculate the probability of putting less than 24 ounces in a cup.
pvalue of Z when X = 24. So



has a pvalue of 0.6915
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.
Answer:
r = 5 cm
Step-by-step explanation:
A = πr²
78.53 = (3.14)r²
divide by 3.14
25 = r²
r = ±5
r = 5
Answer:
0≤x≥3
2≤y≥4
Step-by-step explanation: