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Deffense [45]
4 years ago
14

Solve this, please prove it with steps in detail

Mathematics
1 answer:
statuscvo [17]4 years ago
5 0

Answer:

2

Step-by-step explanation:

-(1-√2) -(2-√3) + 1/√3 + 2+1/2+√5-(√5-√6)-(√6-√7)+ 1/√7+2√2+1/2√2+3

-1+√2-√2+√3-(√3-2)-(2-√5)-√5+√6-√6+√7-(√7-2√2)-(2√2-3)

-1+√2-√2+√3-√3+2-2+√5-√5+√6-√6+√7-√7+2√2-2√2+3

2

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83 and one third percent as a fraction
Dmitriy789 [7]
83 1/3% = (83 1/3)/100    
  = ((3*83 + 1)/3)/100    
<span>  = (250/3)/100    </span>
<span>  = 250/300    </span>
  = (5*50)/(6*50) = (5/6)*(50/50)    
<span>83 1/3% = 5/6</span>
6 0
3 years ago
A soft drink machine outputs a mean of 2323 ounces per cup. The machine's output is normally distributed with a standard deviati
viktelen [127]

Answer:

Area under the normal curve: 0.6915.

69.15% probability of putting less than 24 ounces in a cup.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 23, \sigma = 2

You have been asked to calculate the probability of putting less than 24 ounces in a cup.

pvalue of Z when X = 24. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 23}{2}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915

Area under the normal curve: 0.6915.

69.15% probability of putting less than 24 ounces in a cup.

5 0
3 years ago
Imagine that city officials in your hometown expect a huge rise in population over the next few years. Which of the following pe
ioda

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Step-by-step explanation:

8 0
4 years ago
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The area of a compact disc is 78.53 square centimeters. What is the radius of the disc? Use pi = 3.14
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Answer:

r = 5 cm

Step-by-step explanation:

A = πr²

78.53 = (3.14)r²

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Determine the domain and the range for the relation in interval notation​
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Answer:

0≤x≥3

2≤y≥4

Step-by-step explanation:

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