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Setler79 [48]
4 years ago
6

~~!! i raised the points and i will give brainliest !!~~

Mathematics
1 answer:
weeeeeb [17]4 years ago
7 0

Answer:

r = 3072. A 4 is multiplied times each term to arrive at the next term. OR ... divide a2 by a1 to find the common ratio of 3072. :)

Step-by-step explanation:

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Which ordered pair makes the equation false?
Galina-37 [17]

Answer:

Hi! The correct answer is J and G!

Step-by-step explanation:

<u><em>~I graphed it and it gave me 2 points that we're on this list that were apart of the equation so what wasn't in the equation i wrote here~</em></u>

7 0
3 years ago
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n an orchard, there are 13 apple trees, 21 orange trees, and a cherry tree. What is the ratio of orange trees to cherry trees?
Yuri [45]

Answer:

21 : 1

Step-by-step explanation:

4 0
3 years ago
8(2x- 6)= 96 solve for x
9966 [12]

Answer:

x=9

Step-by-step explanation:

To solve, simplify the equation them isolate x.

8(2x- 6) = 96   Distribute over brackets by multiplying

16x - 48 = 96   Add 48 to both sides

16x = 144         Divide both sides by 16

x = 9                Final answer

5 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
The equation of y= kx and how k=y/x
Jet001 [13]
That’s the same equation but different format.
8 0
4 years ago
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