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2 years ago

Simplify 2(x + 4) + 3(x - 4) 5x - 4 5x 5x + 4

Mathematics

1 answer:

AnnyKZ [126]2 years ago

7 0

The answer to this problem is 5x-4

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Vikki [24]

Similar triangles have corresponding sides with proportional lengths.

AB/BC = DE/EF

5/9 = 7.5/EF

5(EF) = 9 * 7.5

5(EF) = 67.5

EF = 13.5

4 0

2 years ago

Read 2 more answers

Okay last one of these, 15 points xox

Vanyuwa [196]

Answer:

13.2 centimeters

Step-by-step explanation:

Finding the missing side

(?)² + (9)² = (16)²
?² + 81 = 256
?² = 175
? = √175
? = 13.2 centimeters

7 0

1 year ago

Read 2 more answers

Does anyone know this question?

marusya05 [52]

Answer: angle 5 is a 110 degree angle
explanation: angles 3 and 5 are same side interior angles, making them supplementary to each other

6 0

3 years ago

in rectangle PQRS, shown below, the diagonal PR is 15 meters. if the sine of angle SPR is 7/10, what is the value of RS?

lora16 [44]

Answer:sin =perpendicular/hypotenuse

Step-by-step explanation:

Sin angle is given use tan theta or cos theta to find the RS

5 0

2 years ago

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

step 1

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

step 2

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

Find the area of the larger circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

2 years ago