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viva [34]
3 years ago
6

Stephens fraction had a reunion last weekend. If there were 24 family members and 8 apple pies cut into 6 slices, what answer ch

oice represents the fraction of one apple pie that each family member revived? 
Mathematics
1 answer:
Elden [556K]3 years ago
8 0
8*6=42
which is 42 slices of pie in total
24/42=4/7 
which is the fraction of pie each person will have
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A new museum had 7500 vistiors this year.the number of visitors is expected to grow by 5% each year. How many vistiors will be i
Bumek [7]

Answer:

9572 visitors

Step-by-step explanation:

This is exponential: y=aby=ab^x

a = initial value

b = growth rate

It will grow by 5% each year but also keep the same amount as last year (100% of last year's visitors)

a = 7500

b = 1.05

y = 7500(1.05)^x

Plug in x=5

9572.111719 = 9572 visitors

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago
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BRAINIEST + THANK YOU + 5 STARS IF CORRECT
hammer [34]

Answer:

The answer would be that this graph is NOT a proportional relationship.

La respuesta sería que este gráfico NO es una relación proporcional.

Step-by-step explanation:

The reason why this graph makes no relationship is because a relationship needs to be constantly equivalent to the past fraction. But would 2 be equal to 5 and 4 be equal to 10? Nope, that is why it is not a proportional relationship.

La razón por la cual este gráfico no tiene relación es porque una relación debe ser constantemente equivalente a la fracción pasada. ¿Pero sería 2 igual a 5 y 4 igual a 10? No, por eso no es una relación proporcional.

5 0
3 years ago
Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through t
noname [10]

Answer:

a.y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

by(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

Step-by-step explanation:

1.y''-4y'+4y=6x e^{2x}

Auxillary equation

D^2-4D+ 4=0

(D-2)(D-2)=0

D=2,2

Then complementary solution =C_1e^{2x}+C_2xe^{2x}

Particular solution =\frac{6 xe^{2x}}{(D-2)^2}

D is replace by D+2 then we get

P.I=\frac{6xe^{2x}}{0}

P.I=\frac{e^{ax}}{D+a} \cdot .V

where V is a function of x

P.I=\frac}x^3e^{2x}

By integrating two times

Hence, the general solution

y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

b.y''+9y=5 cos x-7 sin x

Auxillary equation

D^2+9=0

D=\pm 3i

C.F=c_1 cos 3x+ c_2sin 3x

P.I=\frac{5 cos x-7 sin x}{D^2+9}

P.I=\frac{sin ax}{D^2+bD +C}

Then  D square is replace by -a square

D^2 is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

4 0
3 years ago
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