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Alex777 [14]
4 years ago
8

On a piece of paper, graph y<-2/5x+1 then determine which answer choice matches the graph you drew

Mathematics
1 answer:
Daniel [21]4 years ago
7 0

Answer:

graph B just took the test

Step-by-step explanation:

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The quality-control manager of a large factory is concerned about the number of defective items produced by workers. Thirty work
kotegsom [21]

Answer:

a. There is no blocking variable, and incentive plans will be randomly assigned to the workers.

Step-by-step explanation:

The Randomized Complete Block Design (RCBD) is a standard experimental design where experimental units or subjects are grouped as blocks (also known as replicates). In RCBD, subjects within each block are randomly assigned to the experimental units within a block. RCBD is a type of design that reduces variability by controlling variation within each treatment, thereby enhancing the estimation of the treatment effects (combinations of the factor levels of the different factors).

6 0
3 years ago
F(x)=4x squared −7x+7, Find f(2)
Lana71 [14]

Answer: 9

Step-by-step explanation:

4x²-7x+7   f(2)=4*(2)^2-7(2)+7=16-14+7=9

7 0
3 years ago
A mixed number has a whole number part and a fractional part. <br>O A. True <br>O B. False​
scoray [572]

Answer: True

Step-by-step explanation:

The statement that a mixed number has a whole number part and a fractional part is true.

The mixed number is made up of a whole number, and a proper fraction. A mixed number simply means a number that is between any two whole numbers. Examples of mixed numbers are 4¾, 7½ etc.

6 0
3 years ago
ABC company manufactures pesticides. The company has used a bright packaging color to distinguish it from other brands. The comp
Bad White [126]

Answer:

It is B or C

Step-by-step explanation:

4 0
2 years ago
One number is 6 more than anouther number. the sum of their squares is 90
Flura [38]
Let x = greater number
      y = smaller  number

(1) x = y + 6&#10;
(1) y = x-6

(2) x^{2} + y^{2} = 90
We'll substitute y in (1) to (2)
(2) x^{2} +  (x-6)^{2} = 90
     x^{2} +  (x^{2} - 12x + 36) = 90
     x^2 + x^2 -12x + 36 - 90 = 0
     2x^2 - 12x -54 = 0&#10;
     2(x^2 - 6x - 27) = 0
     2(x - 9)(x + 3) = 0
 x - 9 = 0        or      x + 3 = 0
      x = 9                        x = -3
and
 y = x - 6                  y = x - 6
 y = 9 - 6                  y = -3 - 6
 y = 3                        y = -9

Therefore, the two numbers can be 9 and 3 or -3 and -9.

      
6 0
4 years ago
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