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3 years ago

What number should be placed in the box to help complete the division calculation?

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

Answer: 935 go in the box.

2635÷17=155

Step-by-step explanation:

935-935=0 which is the last step

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PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

PLEASEEE HELP ME I NEED HELP REAL BAD ON THIS PROBLEM A MILLION THANKS IF YOU HELP ME!!**NO LINKS**THANK YOU SOOOO MUCH!! =D

Sav [38]

Answer:

hmmmmmm look on Firefox

8 0

3 years ago

Aarva cleans 6 apartments in 2.5 hours. how long will it take him to clean 30 apartments

Anon25 [30]

6 apartments in 2.5 hours
30 apartments in ? Hours

6/2.5=30/x
6x=(30)(2.5)
x=75/6
x=12.5 hours

3 0

3 years ago

What is the value of x? Enter your answer in the box. X=

pishuonlain [190]

Answer:

Step-by-step explanation:

2x +2 = 3x - 52

-2x -2x

2 = x -52

+52 +52

50 = x

3 0

3 years ago

Read 2 more answers

Solve this problem: 3(6 - 8)² + 8÷2<br> A-8<br> B-16<br> C-28<br> Will mark Brainliest!!

marishachu [46]

Answer: 16

Step-by-step explanation: When you have a set of parentheses in an order of operations problem, you must simplify what's inside that set of parentheses first before you do anything else.

So our first step here is to subtract 6 - 8 which gives us -2.

So in our next step we have 3 (-2)² + 8 ÷ 2.

Now remember to do exponents before you multiply.

So (-2)² is just -2 × -2 or 4.

So in our next step we have 3 x 4 + 8 ÷ 2.

Now, we multiply so we have 3 x 4 which is 12.

So we have 12 + 8 ÷ 2.

Now we can divide.

8 ÷ 2 is 4 so we have 12 + 4 or 16.

So the answer to this problem is 16.

5 0

4 years ago

Read 2 more answers