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3 years ago

(X+4) over 2, equals 7 X=3 X=5 X=6 X=10

1 answer:

8 0

(x+4)/2=7
multiply 2 to both sides to cancel it out to get this
(x+4)=14
then subtract 4 from both sides to cancel it out and you should get this
x=10

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Please help quickly thanks :)

marusya05 [52]

(0, 0) → t = 0, w = 0 → w = 0 · 0

(1, 4) → t = 1, w = 4 → w = 1 · 4

(2, 8) → t = 2, w = 8 → w = 2 · 4

(3, 12) → t = 3, w = 12 → w = 3 · 4

<h3>Answer: w = 4t</h3>

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3 years ago

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levacccp [35]

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3 years ago

Which line is steeper, Bruce’s or Felicia’s? Whose slope is greater? Does this match the comparison from Part C?

Oksana_A [137]

Answer:

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Step-by-step explanation:

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3 years ago

SOLVE FOR M. please :)

STatiana [176]

Answer:

$m = - 28$

Step-by-step explanation:

$\frac{ - 3}{7} m = 12$

$\frac{ - 7}{3} ( \frac{ - 3}{7})m = \frac{ - 7}{3} \times 12$

$\frac{ - 1}{3} ( - 3)m = \frac{ - 7}{3} \times 12$

$- 1( - 1)m = \frac{ - 7}{3} \times 12$

$1 \times m = \frac{ - 7}{3} \times 12$

$m = \frac{ - 7}{3} \times 12$

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$m = - 28$

<h3>Hope it is helpful....</h3>

3 0

3 years ago

Simplify: −√16x^2 , when x<0

Savatey [412]

Answer:

$-4|x|$

Step-by-step explanation:

To simplify :

$-\sqrt{16x^2}$ , when $x$

In order to simplify the given expression we will take the square root of the term inside the root.

The term in the square root are perfect squares (square of an integer), so, we can write them in square of the numbers.

⇒ $-\sqrt{(\pm4x)^2}$ [As $(\pm4x)^2=16x^2$ ]

On taking square root the square gets removed. So, we have,

⇒ $-(\pm4x)$

⇒ $-4|x|$

Since $x$ , so the value would be negative.

So, simplified answer is

$-4|x|$ (Answer)

3 0

4 years ago