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RoseWind [281]
3 years ago
6

Find the measure of ∠A if

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
8 0
The answer is d as in dog
Harrizon [31]3 years ago
6 0

Answer:

The <em>correct</em> answer is B)65

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On a recent day, 8 euros were worth $11 and 32 euros were worth $44. Enter an equation of the form y = kx to show the relationsh
navik [9.2K]

Answer:

On a recent day, 8 euros were worth $11 and 40 euros were worth $55. Enter an equation of the form y = kx to show the relationship between the number of euros and the value in dollars. First solve k which is the slope so k = ( 55- 11) / ( 40 -8) = 1.375

 Y= 1.375x

Step-by-step explanation:

4 0
3 years ago
Find the slope of a line with x-intercept 5 and y-intercept -3.
Licemer1 [7]

Answer:

3/5

Step-by-step explanation:

When you are given an x-intercept, the y value will always be 0.

When you are given a y-intercept, the x value will always be 0.

With the intercepts we are given, we can make two points we can solve for the slope with.

(5, 0)

(0, -3)

Now, find the slope with the formula [ y2-y1/x2-x1 ]

-3-0/0-5

-3/-5

3/5 or 0.6

Best of Luck!

8 0
3 years ago
Plz Help Me ? With this ?
Sindrei [870]

Answer:

x=9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Will give Brainliest! Just correct answers with a full explanation. A Simple way to solve <img src="https://tex.z-dn.net/?f=4%5E
Amiraneli [1.4K]

4^x-2\cdot5^{2x}-10^x>0

$\implies 2^{2x}-2\cdot5^{2x}-(2^x)(5^x)>0$

let $2^x=a$ and $5^x=b$

So, $a^2-2b^2-ab>0$

divide by $b^2$, ($b^2>0$)

$\implies \left(\frac ab\right)^2-\left(\frac ab\right) -2>0$

this is a quadratic, in $\left(\frac ab\right)$, let it be $x$

So, $x^2-x-2>0$

Can you simplify it now?

8 0
3 years ago
Igloos unlimited charges $150 per night with a 50% discount for every night after the third night .if you stay for days how much
Marina CMI [18]

Answer:

150x,       (x<=3)

225+75x,   (x>3)

*x is the number of nights stayed.

Step-by-step explanation:

-Let the number of days stayed be x.

#If the number of days is equal to or less than 3 days, the cost is:

Cost=C_d\times Days\\\\=150x

Hence, the cost for x>3 is given by 150x

#If the number of days is greater than 3, the the cost is calculated as:

\#First \ 3 \ Days.\\Cost=C_d\times Days\\\\\\=150\times 3\\\\=450\\

\\\#Next \ number \ of \ days\\\\Cost=C_d\times Days\\\\=0.5(150)\times (x-3)\\\\=75(x-3)

We sum the two costs for x>3

\sum{Costs}=450+75(x-3)\\\\=225+75x

Hence, the cost for x>3 is given by 225+75x

6 0
3 years ago
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