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ahrayia [7]
4 years ago
7

PLEASE HELP ASAP!!!! Find the perimeter. Show all work!

Mathematics
1 answer:
telo118 [61]4 years ago
7 0
The perimeter is:  " 331. 2 cm " . 
______________________________________________
<u>Note</u>:
______________________________________________
Perimeter = 34 cm + 34 cm + 95.2 cm + 168 cm = 331.2 cm .
______________________________________________
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Please explain how you came to your answer, need help ASAP. Will give brainliest
shusha [124]
The vertex is the high point of the curve, (2, 1). The vertex form of the equation for a parabola is
.. y = a*(x -h)^2 +k . . . . . . . for vertex = (h, k)

Using the vertex coordinates we read from the graph, the equation is
.. y = a*(x -2)^2 +1

We need to find the value of "a". We can do that by using any (x, y) value that we know (other than the vertex), for example (1, 0).
.. 0 = a*(1 -2)^2 +1
.. 0 = a*1 +1
.. -1 = a

Now we know the equation is
.. y = -(x -2)^2 +1

_____
If we like, we can expand it to
.. y = -(x^2 -4x +4) +1
.. y = -x^2 +4x -3

=========
An alternative approach would be to make use of the zeros. You can read the x-intercepts from the graph as x=1 and x=3. Then you can write the equation as
.. y = a*(x -1)*(x -3)
Once again, you need to find the value of "a" using some other point on the graph. The vertex (x, y) = (2, 1) is one such point. Subsituting those values, we get
.. 1 = a*(2 -1)*(2 -3) = a*1*-1 = -a
.. -1 = a
Then the equation of the graph can be written as
.. y = -(x -1)(x -3)
In expanded form, this is
.. y = -(x^2 -4x +3)
.. y = -x^2 +4x -3 . . . . . . same as above
5 0
4 years ago
A triangle has vertices at (-9,2), (-9,-6), (-3,-6). What is the perimiter of the triangle in units?
vladimir2022 [97]

Answer:

The perimeter is 24 units

Step-by-step explanation:

Given

A = (-9,2) --- (x_1,y_1)

B = (-9,-6) --- (x_2,y_2)

C = (-3,-6) --- (x_3,y_3)

Required

Determine the perimeter

To do this, we calculate the distance AB, BC and AC.

Distance is calculated as:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

So, we have:

AB = \sqrt{(-9 - -9)^2 + (2 - -6)^2

AB = \sqrt{64

AB = 8

BC = \sqrt{(-9 - -3)^2 + (-6 - -6)^2

BC = \sqrt{36

BC = 6

AC = \sqrt{(-9 --3)^2 + (2 --6)^2

AC = \sqrt{100

AC = 10

So, the perimeter (P) is:

P = AB + BC + AC

P =8 + 6 + 10

P =24

3 0
3 years ago
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