Question

What's the largest fraction in eaxh group? a. 5/6 and 29/36 b. 5/12 and 3/8 c.2/5 and 19/45 d.5/7, 13/14, and 19/21

Answer 1

Answer:

a) $\frac{5}{6}$is greatest fraction.

b) $\frac{5}{12}$ is greatest fraction.

c) $\frac{19}{45}$ is greatest fraction.

d) $\frac{13}{14}$ is greatest fraction.

Solution:

To compare two fraction we need to make denominator of both the fraction same.

a)Given fraction are $\frac{5}{6}$ and $\frac{29}{36}$

$\frac{5}{6}=\frac{5 \times 6}{6 \times 6}=\frac{30}{36}$

So $\frac{30}{36}$ is equivalent to $\frac{5}{6}$

So $\frac{30}{36}>\frac{5}{6}$

Hence $\frac{30}{36}$ that is $\frac{5}{6}$ is greater than $\frac{29}{36}$

b)Given fraction are $\frac{5}{12}$ and $\frac{3}{8}$

$\frac{5}{12}=\frac{5 \times 2}{12 \times 2}=\frac{10}{24}$

Similarly we get $\frac{3}{8}=\frac{3 \times 3}{8 \times 3}=\frac{9}{24}$

So $\frac{10}{24}>\frac{9}{24}$

$\frac{10}{24}>\frac{9}{24}$

That is $\frac{5}{12}>\frac{3}{8}$

Hence $\frac{5}{12}$ is greater than $\frac{3}{8}$

c) Given fraction are $\frac{2}{5}$ and $\frac{19}{45}$

$\frac{2}{5}=\frac{2 \times 9}{5 \times 9}=\frac{18}{45}$

So $\frac{19}{45}>\frac{18}{45}$

That is $\frac{19}{45}>\frac{2}{5}$

Hence $\frac{19}{45}$ is greater than $\frac{2}{5}$

d)Given fraction are $\frac{5}{7}$, $\frac{13}{14}$ and $\frac{19}{21}$

$\frac{5}{7}=\frac{5 \times 6}{7 \times 6}=\frac{30}{42}$

$\frac{13}{14}=\frac{13 \times 3}{14 \times 3}=\frac{39}{42}$

Similarly we get  

$\frac{19}{21}=\frac{19 \times 2}{21 \times 2}=\frac{38}{42}$

So $\frac{39}{42}>\frac{38}{42}>\frac{30}{42}$

That is $\frac{13}{14}>\frac{19}{21}>\frac{5}{7}$

Hence $\frac{13}{14}$ is greatest fraction.