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2 years ago

1/2 times a for a = 3/10

2 answers:

3 0

Since you are multiplying a fraction with another, all you have to do is cross multiply. First, set it up:
1 3
_ _
2 10
Multiply straight across and that would equal 3/20. Since it cannot be simplified, 3/20 is the final answer. Hope this helped. Cheers, mimiisawesome5

nikdorinn [45]2 years ago

3 0

3/20 it cant be simplified I think...

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True or false: the height is always twice the length of the base edge for any triangular pyramid

AleksandrR [38]

Answer:

FALSE

Step-by-step explanation:

The length of the base edge of a triangular pyramid may vary.

The height is not always twice the length of the base edge for any triangular pyramid, the dimensions are not fixed for any shape and can vary from one design to another.

more so, i may require a particular size or dimension of triangular based pyramid for my application that may not suit your application.

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3 years ago

Which of the numbers below are exactly divisible by 9?

ss7ja [257]

B and C can be divided by 9.

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3 years ago

Read 2 more answers

In this problem,y = 1/(x2 + c)is a one-parameter family of solutions of the first-order DEy' + 2xy2 = 0.Find a solution of the f

trasher [3.6K]

Differentiate the given solution:

$y=\dfrac1{x^2+C}\implies y'=-\dfrac{2x}{(x^2+C)^2}$

Substitute $y$ and $y'$ into the ODE:

$-\dfrac{2x}{(x^2+C)^2}+2x\left(\dfrac1{x^2+C}\right)^2=0$

and it's easy to see the left side indeed reduces to 0.

6 0

2 years ago

A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he

Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as $R(x)=80x-0.2x^ 2$ . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ $R(x)=80x-0.2x^ 2$

⇒ $\frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}$

⇒ $\frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}$

⇒ $0=80-2x(0.2)$

⇒ $\frac{80}{0.4}=x$

⇒ $x=200$

Now , Value of function at x=200 is :

⇒ $R(200)=80(200)-0.2(200)^ 2$

⇒ $R(200)=16000-8000$

⇒ $R(200)=8000$

Therefore , The maximum units is 200 and , Total revenue is $8,000

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2 years ago

Please Help Solve <br> 8 = 7/6 (b)

sukhopar [10]

B=48/7 you simplify 7/b(b) to 7b/6
Then multiply both sides by 6 so 8 x 6 =7b then simplify 8 x 6 =48
And divide both sides by 7 48\7 then switch sides b=48/7

4 0

2 years ago