Question

What is the surface area of a right circular cylinder with a height of 8 meters and a base whose

Answer 1

Answer:

$S.A=96\pi m^2$

Step-by-step explanation:

The surface area of a right circular cylinder is given by the formula;

$S.A=2\pi r(r+h)$

where $h=8m$ is the height of the cylinder and

$r=4m$ is the radius of the cylinder.

We plug in these values into the formula to obtain;

$S.A=2\pi \times4(4+8)$

$S.A=8 \times12 \pi$

$S.A=96\pi m^2$