Answer:


Step-by-step explanation:
Given

Solving (a): The mean of the 6 samples.
This is calculated as:

So, we have:



Solving (b): The sample standard deviation.
This is calculated using:

So, we have:




Using the z-distribution, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
Researching this problem on the internet, 8 out of 39 candies are red, hence the sample size and the estimate are given by:

Hence the bounds of the interval are:
As a percentage, the 95% confidence interval for the percentage of red candies is of (7.84%, 33.18%). Since 33% is part of the interval, there is not enough evidence to conclude that the claim is wrong.
More can be learned about the z-distribution at brainly.com/question/25890103
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Question:
Mancini's Pizzeria sells four types of pizza crust. Last week, the owner tracked the number sold of each type, and this is what he found.
Type of Crust Number Sold
Thin crust 312
Thick crust 245
Stuffed crust 179
Pan style 304
Based on this information, of the next 4500 pizzas he sells, how many should he expect to be thick crust? Round your answer to the nearest whole number. Do not round any intermediate calculations.
Answer:
1060 thick crusts
Step-by-step explanation:
Given
The above table
Required
Expected number of thick crust for the next 4500
For last week data, calculate the proportion of thick crust sold




For the next 4500;

The expected number of thick crust is (E(x)):



Answer:
25 times .10 = 2.5 (22.5) 22.5-1.00= 21.5
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
This is an eye scanning