Question

Use substitution to solve the system of equations x= -3y-13 2x+2y=-6

Answer 1

For this case we have a system of two equations with two unknowns:

$x = -3y-13\\2x + 2y = -6$

To solve we follow the steps below:

We substitute the first equation in the second:

$2 (-3y-13) + 2y = -6$

We apply distributive property to the terms of parentheses:

$-6y-26 + 2y = -6$

We add 26 to both sides of the equation:

$-6y + 2y = -6 + 26\\-4y = 20\\y = \frac {20} {- 4}\\y = -5$

We find the value of x:

$x = -3 (-5) -13\\x = 15-13\\x = 2$

Answer:

$(x, y) :( 2, -5)$