How do I solve 6v-5/8=7/8
1 answer:
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Answer:
The equation in standard form is
Step-by-step explanation:
The distance from (-1, 12) to (-1, 8) = 4 = diameter of the circle. So, 2 = radius
The center of the circle is at (-1, 10)
The equation in standard form is
Answer:
The quadratic equation form is x² - 9 x + 14 = 0
Step-by-step explanation:
Given in the question as ,
The solution of quadratic equation are x = 2 and x = 7
The constant K is a non-zero number
Now , let the quadratic equation be , ax² + bx + c = 0
And sum of roots =
product of roots =
So, 2 + 7 =
Or, 2 × 7 =
I.e = 9 ,
= 14
Or, b = - 9 a And c = 14 a
Put this value of b and c in standard form of quadratic equation
I.e ax² + bx + c = 0
Or, ax² - 9 ax + 14 a = 0
Or , a ( x² - 9 x + 14 ) = 0
∴ a = 0 And x² - 9 x + 14 = 0
Hence , The quadratic equation form is x² - 9 x + 14 = 0 Answer