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Nina [5.8K]
3 years ago
5

What ls 6q+m-m; use m=8and q =3

Mathematics
1 answer:
SpyIntel [72]3 years ago
6 0
First of all, I see  +m  and  -m  on the left side, and I realize that when you combine those, they make zero-m.  So you can ignore them completely,
and that means that the value of 'm' has no effect on the value of that
expression.  It doesn't matter whether 'm' is  2.509  or 'm' is  8  or 'm'
is 9 hundred trillion.  Either way, the expression has the same value.

The value is   6q = 6(3) = <em>18</em> .
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The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard d
Misha Larkins [42]

Answer:

14.69% probability that defect length is at most 20 mm

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 28, \sigma = 7.6

What is the probability that defect length is at most 20 mm

This is the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 28}{7.6}

Z = -1.05

Z = -1.05 has a pvalue of 0.1469

14.69% probability that defect length is at most 20 mm

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Step-by-step explanation:

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There were 15 peple at a party and 4 1/2 pizzas. If the pizza's were shared out equally, what fraction will each person get?
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Step-by-step explanation:

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A woman is worried that she might have breast cancer. The standard test for breast cancer is mammography. From research she foun
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Answer:

PPV= 0.432

Step-by-step explanation:

Hello!

Remember:

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true positive rate).  

⇒ P(+/S) =<u> P(+ ∩ S) </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)  

⇒ P(-/H) =<u> P(- ∩ H) </u>

                     P(H)

Positive predictive value (PPV)

The prevalence of the sickness can be expresed as the probability of being sick in the population of interest.

It's defined as the probability of being sick when the test is positive:

P(S/+)=<u> P(S ∩ +)  </u>

               P(+)

In this case, the population of interest is "Women in their forties"

The probability of being sick is P(S)= 1 /52= 0.019

The sensibility of this test is P(+/S)= 0.86

The specificity of the test is P(-/H)= 0.97

To calculate the positive predictive value you have to reach the probability of being sick and the test is positive. You can clear this probability using the information of the sensibility of the test and the prevalence of the sickness in the population:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+ ∩ S)<u> </u>=P(+/S) * P(S) = 0.86*0.019= 0.016

Now you need to calculate the probability of the test being positive P(+)

You can calculate it as: P(+)= P(+ ∩ S) + P(+ ∩ H)

P(+ ∩ H)= P(H) - P(- ∩ H)

The probability of the person being healthy P(H) is complementary to the prevalence of the sickness, symbolically: P(H)= 1 - P(S)= 1 - 0.019= 0.981

Now using the information of the test specificity and the probability of being healthy you can clear P(- ∩ H)

P(- ∩ H)= P(H)*P(-/H) = 0.981*0.97= 0.95157≅0.96

P(+ ∩ H)= P(H) - P(- ∩ H)= 0.981-0.96= 0.021

P(+)= P(+ ∩ S) + P(+ ∩ H)= 0.016+0.021= 0.037

The PPV of the test is:

P(S/+)=<u> P(S ∩ +)   </u>=<u> 0.016 </u>= 0.432

               P(+)         0.037

I hope it helps!

4 0
3 years ago
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