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mart [117]
3 years ago
8

PROBLEM 1: Looking at different combinations of letters we can decide certain facts. Decide how many different "words" can be fo

rmed using all the letters from the word PARSLEY they do not have to mean anything) and how many'words" can be formed using all the letters from the word PEPPER (they do not have to mean anything) NOTE: the 2 answers are different because Parsley does not have repeating letters and pepper does. Give the number of words you can form from each and how you got that number HINT: If you have trouble getting started, do the excersize for the words WOW and WET to help see the pattern.
Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

The words from parsley are PAR, YES, RAP, PAY,and SLAP

The words from pepper are PEEP and that is it

Step-by-step explanation:

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A,C,D

Step-by-step explanation:

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A ski patrol unit has seven members available for duty, and two of them are to be sent to rescue an injured skier. In how many w
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Step-by-step explanation:

7C2 = 21

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Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
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Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

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Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

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Answer:

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Step-by-step explanation:

Here you go.

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