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irga5000 [103]
3 years ago
13

Can sumone help Mii wit thiss??

Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
Equal them to each other
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To which subsets of real numbers does the following number belong? square root of 30
LenaWriter [7]

In order to determine which subset it belongs, we must rewrite

\sqrt(30)

as

\sqrt(30)=\sqrt(2\times \times 3 \times 5)


\Rightarrow \sqrt(30)=\sqrt(2 \times 3\times 5)

\Rightarrow \sqrt(30)=\sqrt(2) \times \sqrt(3) \times \sqrt(5)


All these three numbers are irrational numbers, hence their product is also irrational


<h2>\Rightarrow \sqrt(30)</h2><h2>belongs to the set of irrational numbers</h2>
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Answer:

answer is 13 plus 26 is equal to 39

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Eric created a rectangular patio using 1 foot square paving stones,which are sold in batches by the dozen. The patio measures 7
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6 0
3 years ago
Algebra 1 question 4.
Brrunno [24]

Greetings!

To start this problem, let's first assign a variable for the missing, consecutive odd numbers. Since they are consecutive and odd, we add two.

<u>Proof:</u> <em>3-1=2, 5-3=2</em>

The first, consecutive, odd number: x

The second, consecutive, odd number: x+2

The third, consecutive, odd number: x+4

The fourth, consecutive, odd number: x+6

The sum of the values are equal to 3 times the sum of the first two numbers, of which this is equal to 35 less than the fourth number. Let's create an equation to simplify this:

3((x)+(x+2))=(x+6)-35

Complete the operations inside the parenthesis:

3(2x+2)=(x+6)-35

Distribute the parenthesis (utilizing the distributive property)

(((2x)(3))+((2)(3)))=(x+6)-35

(6x+6)=(x+6)-35

Simplify both sides:

6x+6=x-29

Add -6 and -x to both sides of the equation:

(6x+6)+(-6)+(-x)=(x-29)+(-6)+(-x)

5x=-35

Divide both sides of the equation by 5:

\frac{5x}{5}=\frac{-35}{5}

x=-7

If x is equal to -7:

x+2=-5

x+4=-3

x+6=-1

The four numbers are:

\boxed{-7,-5,-3,-1}

I hope this helps!

-Benjamin

4 0
3 years ago
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