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iragen [17]
3 years ago
13

Which of the following is a true statement of the figure​

Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

Step-by-step explanation:

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PLEASE answer these math questions
zysi [14]
1. To find the square root, you have to square root them both.

Square root of 324 is 18, so x=-18, 1818

2. Divide 49 by 9. 49/9=5.44 then find the square root of 5.44 which is 2.3, x=-2.3, 2.3.

3. To do this one it is one of either 2 or 4 because it is not a perfect square, it can break down to square root of 16 and square root of 6, which then makes it +-4 square root 6.

4. This one is simple the square root of 34 is 5.8

5. Subtract each by 5 to get 6y^2=215 then divide each by 6. Y^2=34.8 then square root. Which makes y=+-5.9. Hope this helped.
3 0
3 years ago
How do you do this. please help
puteri [66]
The solution is when they intersect.  So to find the answer, set each equation equal to each and solve:

-2x + 3 = x^2 -6x + 3
3 = x^2 -4x + 3
0 = x^2 -4x
0 = x(x-4)

So the solutions are x = 0 and x = 4

Plug in these values into the easier equation to solve for the y's

x = 0 into -2x + 3 gives y = 3
So one solution is (0, 3)

x = 4 into -2x + 3 gives y = -5
So the second solution is (4, -5)
3 0
3 years ago
We assume each month is equally likely to be a student’s birthday month. i) The number of ways ten students can have birthdays i
snow_lady [41]

Answer:

The solutions are correct

Step-by-step explanation:

i) In a year there is a total of 12 months, if ten students can have birthdays in 10 different months, the number of ways this can happen is:

Number of ways = 12 × 11 × 10 × . . . × 3 = \frac{12!}{2!}

ii) The number of ways 1 student can have birthday months = 12¹, The number of ways 2 students can have birthday months = 12¹ × 12¹ = 12². Hence:

The number of ways 10 students can have birthday months = 12¹⁰

iii) The probability that no two share a birthday month = \frac{12!}{2!*12^{10}} = 0.00387

7 0
3 years ago
Explain how to find the value of y that would make segment OP parallel to segment LN.
photoshop1234 [79]

Answer:

y = 36

Step-by-step explanation:

Given; the triangle above

Required

Find y

This question falls under the topic/subtopic similar triangles where we need to make comparison between similar sides'

But first, it should be noted that triangle MOP is similar to triangle MLN

This implies that

Side MP is similar to MN

Side MO is similar to  ML

Mathematically; This can be represented as follows;

\frac{MP}{MN} = \frac{MO}{ML}

Where MP =y; MN = y + 18; MO = 28; ML = 28 + 14

Substitute these values in the above expression

\frac{y}{y+18} = \frac{28}{28+14}

\frac{y}{y+18} = \frac{28}{42}

Multiply both sides by 42

42 * \frac{y}{y+18} = \frac{28}{42} * 42

\frac{42y}{y+18} = \frac{28*42}{42}

\frac{42y}{y+18} = 28

Multiply both sides by y + 18

(y+18)*\frac{42y}{y+18} = 28 * (y+18)

42y = 28 * (y+18)

Open Bracket

42y = 28 * y+28 * 18

42y = 28y+504

Subtract 28y from both sides

42y - 28y = 28y - 28y +504

14y = 504

Divide both sides by 14

\frac{14y}{14} = \frac{504}{14}

y = \frac{504}{14}

y = 36

3 0
3 years ago
Read 2 more answers
How do you transpose a number
Mrac [35]

Answer:

Transposing a number is a type of error where two digits swap position in the sequence. An example would be to enter 13 instead of the desired 31. It could also be the error of dropping a needed zero as in writing 15 instead of the desired 150.

Step-by-step explanation:

Unless by "number" you mean musical score. Then transposing is rewriting the score in a new key.

7 0
3 years ago
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