Answer;
-Malachite green
Explanation;
-Malachite green is also used in endospore staining, since it can directly stain endospores within bacterial cells; here a safranin counterstain is often used.
-Because of their tough protein coats made of keratin, spores are highly resistant to normal staining procedures. The primary stain in the endospore stain procedure, malachite green, is driven into the cells with heat.
B. glycolysis is the answer
Answer:
(a) (Glu)zo or(Phe-Met)3 at pH 7.0
O (Glu)zo ✔
O (Phe-Met)s ❌
(b) (Gly) zo or (Lys-Ala)3 at pH 7.0:
O (Gly12) ❌
O (Lys-Ala)✔
(c) (Ala-Asp-Gly)s or (Asn-Ser-His)s at pH 3.0:
O (Asn-Ser-His)s ✔
O (Ala-Asp-Gly)s ❌
(d) (Ala-Ser-Gly)s or (Asn-Ser-His)s at pH 6.0:
O(Ala-Ser-Gly)s ❌
O (Asn-Ser-Hish)s ✔
Explanation:
Polypeptides that has polar or charged side chains are more soluble than polypeptides with nonpolar side chains.
(a) At ph 7.0
(Glu)20 is negatively charged at pH 7 and more soluble
(Phe-Met)3 is observed to be less polar and less soluble
(b)At ph 7.0
(Lys-Ala)3 is positively charged (polar) and more soluble
(Gly)20 is uncharged as only the amino- and carboxyl-terminal groups are charged as its less polar and less soluble too.
(c) At pH 6.0
(Asn-Ser-His)5 has polar Asn side chains and partially protonated His side chains and it's more soluble unlike the (Ala-Asp-Gly)s at that pH.
(d) At pH 3.0
(Asn-Ser-His)s as partially protonated carboxylate groups of Asp residues and it is also neutral but the imidazole groups of His residues are fully protonated and positively charged. Hence it's more soluble than the (Ala-Ser-Gly)s at that particular pH.
Answer:
a. Acetyl-CoA
Explanation:
Pyruvate is decarboxylated in the matrix of mitochondria and loses its carbon as CO2. This decarboxylation is accompanied by its oxidation as well. This process of oxidative decarboxylation of pyruvate is catalyzed by an enzyme complex. It is called the pyruvate dehydrogenase enzyme complex. NAD+ accepts the released electrons and pyruvate is converted into energy-rich acetyl CoA which in turn enters into the Kreb's cycle.
