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attashe74 [19]
3 years ago
14

With ____ editing, Word automatically displays a Paste Options button near the pasted or moved text.

Computers and Technology
1 answer:
harina [27]3 years ago
8 0
The answer is drag and drop. 
 With drag and drop editing, word automatically displays a paste option button near the pasted or moved text. 
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Discuss one simple example of hybrid computer.​
andrezito [222]

Answer:

thermometer , petrol pump

5 0
3 years ago
Which word processing tool can help you find synonyms to improve your word choice?
deff fn [24]
Grammarly is the answer
6 0
3 years ago
Read 2 more answers
The ____ is the period of time within which systems, applications, or functions must be recovered after an outage. Select one:
scZoUnD [109]

Answer:

c. recovery time objective                                                  

Explanation:

  • Recovery time objective (RTO) is the maximum acceptable duration permitted between an unfortunate loss or failure and the restoration of normal operations and services.
  • According to the RTO, the systems, applications or operations must be restored within a targeted time period after a disaster, to avoid unacceptable outcomes of the disruption.
  • So a business process must be recovered within this period of time.
  • It measures how much a failure affects the normal operations, applications and systems and RTO is measures in time units like seconds minutes hours or days.
  • In simple words RTO refers to the time you need to restore system, applications and data.
  • For instance a 2-hour RTO refers to restore and get operations or services back to running within 2 hours of the service failure or outrage.
6 0
3 years ago
Use semaphore(s) to solve the following problem. There are three processes: P1, P2, and P3. Each process Pi has a segment of cod
Lisa [10]

Answer:

See explaination

Explanation:

Here we will use two semaphore variables to satisfy our goal

We will initialize s1=1 and s2=1 globally and they are accessed by all 3 processes and use up and down operations in following way

Code:-

s1,s2=1

P1 P2 P3

P(s1)

P(s2)

C1

V(s2) .

P(s2). .

. C2

V(s1) .

P(s1)

. . C3

V(s2)

Explanation:-

The P(s1) stands for down operation for semaphore s1 and V(s1) stands for Up operation for semaphore s1.

The Down operation on s1=1 will make it s1=0 and our process will execute ,and down on s1=0 will block the process

The Up operation on s1=0 will unblock the process and on s1=1 will be normal execution of process

Now in the above code:

1)If C1 is executed first then it means down on s1,s2 will make it zero and up on s2 will make it 1, so in that case C3 cannot execute because P3 has down operation on s1 before C3 ,so C2 will execute by performing down on s2 and after that Up on s1 will be done by P2 and then C3 can execute

So our first condition gets satisfied

2)If C1 is not executed earlier means:-

a)If C2 is executed by performing down on S2 then s2=0,so definitely C3 will be executed because down(s2) in case of C1 will block the process P1 and after C3 execute Up operation on s2 ,C1 can execute because P1 gets unblocked .

b)If C3 is executed by performing down on s1 then s1=0 ,so definitely C2 will be executed now ,because down on s1 will block the process P1 and after that P2 will perform up on s1 ,so P1 gets unblocked

So C1 will be executed after C2 and C3 ,hence our 2nd condition satisfied.

4 0
3 years ago
c programming Write code that prints: Ready! countNum ... 2 1 Go! Your code should contain a for loop. Print a newline after eac
olga_2 [115]

Answer:see explanation

Explanation:

Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.

The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!

#include <stdio.h>

int main(void)

{

   int countNum;

   int i;

   countNum = 22;

   for ( i = countNum; i > 0; i--) {

       if (i == countNum){

           printf("Ready!\n");

       }

       printf("%d\n",i);

   }

   printf("Go!\n");

   return 0;

}

6 0
3 years ago
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