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miss Akunina [59]
4 years ago
15

A 2- inch radius circle is drawn inside a 6- inch radius circle. If you throw a dart at these circles, what is the probability y

ou land inside the smaller circle?
Mathematics
1 answer:
GalinKa [24]4 years ago
7 0

Answer:

The probability is 11.11\%  or  1/9

Step-by-step explanation:

we know that

To find the probability divide the area of the smaller circle by the area of the larger circle

so

The area of a circle is equal to

A=\pi r^{2}

step 1

Find the area of the smaller circle

A=\pi (2)^{2}=4\pi\ in^{2}

step 2

Find the area of the larger circle

A=\pi (6)^{2}=36\pi\ in^{2}

step 3

Divide the area of the smaller circle by the area of the larger circle

4\pi\ in^{2}/36\pi\ in^{2}=1/9=11.11\%

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Answer:

90 seconds

Step-by-step explanation:

If James eats 32 hotdogs in 60 seconds, we want to find how long it would take James to eat 48 hotdogs.

We can use proportion to solve this problem.

If 32:60, then 48:x.

Since it will required more seconds to eat 48 hotdogs, 32 will divide.

If more, less divides.

Therefore

x =  \frac{48 \times 60}{32}

x = 90

Therefore it will take James 90 seconds if he eats at the same rate

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3 years ago
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Answer: 1x 10

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Step-by-step explanation:

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3 years ago
The Student Monitor surveys 1200 undergraduates from 100 colleges semiannually to understand trends among college students. Rece
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Answer:

A sample size of 385 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

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In which \sigma is the standard deviation of the population and n is the size of the sample.

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A sample size of n is needed. n is found when M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.96\frac{10}{\sqrt{n}}

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3 years ago
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Answer:

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3 years ago
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earnstyle [38]
Series is 15, 12, 9…,
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By Arithmetic progression

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3 years ago
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