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vagabundo [1.1K]
2 years ago
10

A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the ba

rbell. The chain has a total weight of 500 N. How much work (in J) is required to lift the barbell to a height of 2 m?
Mathematics
1 answer:
masha68 [24]2 years ago
5 0
In physics, work is equal to the product of force and distance, given that the direction of force is the same with the direction of the distance.

W = Fd

The total force is 
F = 1,700 N + 500 N = 2,200 N
Now, if the question is the work needed to lift the barbell from the ground, the distance would be 2 m. Hence, the work would be

W = (2,220 N)(2 m) = 4,400 N·m or 4,400 J
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A line segment that has both endpoints on the circumference
AlexFokin [52]

Answer:

A chord

Step-by-step explanation:

By the definition of a chord, it is a line segment whose endpoints lie on the circle, (and in this case circle is meant by the set of points equidistant from a center point, or as an algebraic term: circumference)

5 0
3 years ago
Which of the following expressions is NOT equivalent to (x − 6)(x − 3)?
kodGreya [7K]

Answer:

B. x(x) + (−6)(−3)

NOT equivalent  to (x − 6)(x − 3)

Step-by-step explanation:

(x − 6)(x − 3)

= x^2 - 3x - 6x + 18

= x^2 - 9x + 18

A. (6 − x)(3 − x)

= 18 - 6x - 3x + x^2

= 18 - 9x + x^2

= x^2  - 9x + 18  ---->equivalent  to (x − 6)(x − 3)

B. x(x) + (−6)(−3)  = x^2 + 18   ----> NOT equivalent  to (x − 6)(x − 3)

C. x2 − 3x − 6x + 18   = x^2 - 9x + 18  --> equivalent  to (x − 6)(x − 3)

D. x(x − 6) − 3(x − 6)

= x^2 - 6x - 3x + 18

= x^2  - 9x + 18  ---->equivalent  to (x − 6)(x − 3)

4 0
2 years ago
If a phone plan allows for 698 minutes each month, and Jorge uses 475 minutes by the end of the second week, what percent of his
Juli2301 [7.4K]
Well I'm doing it an easy way but 50% or half of 698 is about 350.

475 is slightly above 350 so the answer would be 68%
5 0
3 years ago
30 POINTS! Combine the like terms of the 2 questions below:
astraxan [27]

Answer:

\tt 1)\: \boxed{\tt 4y+10}

\tt 2)\:\boxed{\tt 0.5x^4+10.5}

Step-by-step explanation:

1) y + 4 + 3(y + 2)

Expand:-

\tt y+4+3y+6

Combine like terms:-

\tt y+3y+4+6

\boxed{\tt 4y+10}

__

2) 0.5(x⁴ - 3) + 12

Expand:-

\tt 0.5x^4-1.5+12

Add/Subtract Numbers:-

\boxed{\tt 0.5x^4+10.5}

___________________

5 0
2 years ago
Which of these points lies on the circle with the center (2,3) and radius 2?
yan [13]

Answer:

The answer to your question is the letter A.

Step-by-step explanation:

Data

Center = (2, 3)

radius = 2

Process

1.- Find the equation of the line

              (x - h)² + (y - k)² = r²

-Substitution

              (x - 2)² + (y - 3)² = 2²  

-Simplification

              (x - 2)² + (y - 3)² = 4

-Evaluate the points in the equation

A. (4, 3)

              (4 - 2)² + (3 - 3)² = 4

                   2² + 0 = 4

                           4 = 4     This point lies in the circle

B (-1, 0)

              (-1 - 2)² + (0 - 3)² = 4

                        -3² + (-3)² = 4

                          9 + 9 = 4   This point is not part of the circle

C. (1, 3)

              (1 - 2)² + (3 - 3)² = 4

                 (-1)² + (0)² = 4

                            1 = 4          This point is not part of the circle

D. (3, 4)

              (3 - 2)² + (4 - 3)² = 4

                     1² + 1² = 4

                            2 = 4          This point is not part of the circle

5 0
3 years ago
Read 2 more answers
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