Ask question

Ask question

All categories

3 years ago

11

Water has a density of about 0.0361 pounds/cubic inch. You might know that wood floats on water. What can you conclude about the

densities of objects that float and the densities of objects that do not?

1 answer:

masya89 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:

Float on water: d < 0.0361 lb/in³ (where d denotes denisity)

Do not float on water: d > 0.0361 lb/in³

You might be interested in

HELP. Pleaseee. I have no idea what this means.

Vilka [71]

Answer:

2

Step-by-step explanation:

roots are the intercepts at the x axis I believe

8 0

2 years ago

A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability o

andrezito [222]

Answer:

0.07

Step-by-step explanation:

First, add up all the numbers. This will be the denominator.

4+2+3=9

There are 9 pieces of candy.

Since you are randomly choosing two times you will have to multiply two fractions.

There are $\frac{2}{9}$ M&M's, and $\frac{1}{3}$ Butterfingers (You simplify)

Now you multiply these.

$\frac{2}{9}$ × $\frac{1}{3}$ = $\frac{2}{27}$

Now make this into a decimal. To do this divide 2 and 27. which is approximately 0.07.

8 0

3 years ago

6. Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined, enter UND

Darya [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

6a

$V(3) = 113.112$

6b

$V(\frac{3}{2}) = 14.139$

6c

$V(2r) = 33.514r^3$

7a

$h(5) = 0$

7b

$h(t) = -5.76$

7c

$h(x+5) = x(x+5)$

Step-by-step explanation:

Considering the question 6

The function given is $V(r) = \frac{4}{3} \pi r^3$

For V(3) we have

$V(3) = \frac{4}{3} \pi 3^3$

$V(3) = \frac{4}{3} * 3.142 * 3^3$

$V(3) = 113.112$

For $V(\frac{3}{2})$

$V(\frac{3}{2}) = \frac{4}{3} * \pi * (\frac{3}{2})^3$

$V(\frac{3}{2}) = \frac{4}{3} * 3.142 * (\frac{3}{2})^3$

$V(\frac{3}{2}) = 14.139$

For V(2r)

$V(2r) = \frac{4}{3} \pi (2r)^3$

$V(2r) = \frac{4}{3} * 3.142*8r^3$

$V(2r) = 33.514r^3$

Considering the question 7

The function given is $h(t) = t^2 - 5t$

For h(5)

$h(5) = 5^2 - 5(5)$

$h(5) = 0$

For h(1.8)

$h(t) = 1.8^2 - 5(1.8)$

$h(t) = -5.76$

For h(x+ 5)

$h(x+5) = (x+5)^2 - 5(x+5)$

$h(x+5) = x^2 + 25+10x-5x-25$

$h(x+5) = x(x+5)$

7 0

3 years ago

Which equation has solution x = -3?

vladimir1956 [14]

Hi Brainiac

1/2(2x-6) = -6
We need to distribute
(1/2)(2x) + (1/2)(-6) = -6
2x/2 + -6/2 = -6
x - 3 = -6
x = -6 + 3
x = -3
Thus, The answer is D

I apologize for the late answer :(

7 0

3 years ago

What is the simplified expression for the <br>expression below? 4(x+8)+5(x-3)

ArbitrLikvidat [17]

4(x+8)+5(x-3)
= 4x+32+5(x-3)
=4x+32+5x-15
=9x+17

Answer: 9x+17

4 0

3 years ago