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3 years ago

11

Four hours are pulling a wagon . Each horse drinks 45,000 millimeters of water each day. How many liters of water will the horse

s drink in 5 days

2 answers:

Diano4ka-milaya [45]3 years ago

8 0

I don't know you tell me

Andreas93 [3]3 years ago

4 0

225,000 if my memory serves me correctly

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Evaluate 13-0.5w+6x when w=10 and x=1/2

Rus_ich [418]

Ok so first you need to put w and x in the equation —-> 13-0.5(10)+6(1/2) and now you just solve -0.5 times 10 is -5 so 13-(-5)+6(1/2) now multiply 6 times 1/2 which is 3 so now we have 13-(-5)+3= 21

6 0

3 years ago

Read 2 more answers

The water level in a lake was monitored and was noted to have changed -2 1/3 inches in one year. The next year it was noted to h

Diano4ka-milaya [45]

Answer:

The total change in water level over the past 2 years is $\displaystyle -4 \frac{1}{6}$ .

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Fractions

Proper and Improper

Numbers

Least Common Multiple (LCM)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Year 1 water change: $\displaystyle -2 \frac{1}{3}$

Year 2 water change: $\displaystyle -1 \frac{5}{6}$

<u>Step 2: Find Total Water Change</u>

[Set up] Add yearly water changes: $\displaystyle -2 \frac{1}{3} + -1 \frac{5}{6}$
[Fractions] Convert to improper: $\displaystyle \frac{-7}{3} - \frac{11}{6}$
[Fraction] Rewrite [LCM]: $\displaystyle \frac{-14}{6} - \frac{11}{6}$
[Order of Operations] Subtract: $\displaystyle \frac{-25}{6}$
[Fraction] Convert to proper: $\displaystyle -4 \frac{1}{6}$

5 0

3 years ago

Please help Find: ∠x ∠a ∠b

V125BC [204]

Answer:

your answer

don't forget to mark brainliest✌️✌️

7 0

4 years ago

$6000 is invested in an account that earns 4.5% annual interest, compounded continuously. What is the value of the account after

mario62 [17]

Answer:

Convert 4.5% to a decimal. 6000,0.045, 8 years

Step-by-step explanation:

I used math--way

8 0

3 years ago

- Given a test statistic of t= 3.018 of a left-tailed test with n= 13, use a 0.01 significance level

alina1380 [7]

Using the t-distribution, it is found that the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:

$H_0: \mu = 85$

We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:

$H_1: \mu < 85$

<h3>What is the decision?</h3>

The test statistic is of t = -3.018.

Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.

The p-value is <u>less than 0.01</u>, hence the null hypothesis is rejected and the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

More can be learned about the t-distribution at brainly.com/question/16313918

5 0

2 years ago