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Neko [114]
3 years ago
12

This picture shows a cube and its net

Mathematics
2 answers:
fenix001 [56]3 years ago
5 0

The formula is 6 a^2

6 x (11^2)

11 x 11=121

6 x 121 = 726

So 726 is your answer

Illusion [34]3 years ago
4 0

The surface area of the shape made of 6 cubes is \boxed{726{\text{ c}}{{\text{m}}^2}}.

Further explanation:

The formula for the surface area of the cube can be expressed as follows,

\boxed{{\text{Surface Area}} = {{\left( {{\text{Side}}} \right)}^2}}

Given:

The options are given as follows.

A. 11{\text{ c}}{{\text{m}}^2}

B. 66{\text{ c}}{{\text{m}}^2}

C. 726{\text{ c}}{{\text{m}}^2}

D. 1331{\text{ c}}{{\text{m}}^2}

Explanation:

The side of the cube is 11{\text{ cm}}.

The surface area of one box can be obtained as follows,

\begin{aligned}{\text{Surface area}}&= {\left( {11} \right)^2}\\&= 121{\text{ c}}{{\text{m}}^2}\\\end{aligned}

There are 6 cubes in the given shape.

The surface area of the shape can be obtained as follows,

\begin{aligned}{\text{Surface Area of shape}}&= 6\times 121\\&= 726{\text{ c}}{{\text{m}}^2}\\\end{aligned}

The surface area of the shape made of 6 cubes is \boxed{726{\text{ c}}{{\text{m}}^2}}.

Option A is not correct.

Option B is not correct.

Option C is correct.

Option D is not correct.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Mensuration

Keywords: cube, cuboid, surface area, volume of the cube, picture shows cube, side of the cube, total surface area, curved surface area.

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Answer:

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What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

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<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

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 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

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