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Softa [21]
3 years ago
14

When bands play at the arena the money made from ticket sales is split in an agreed ratio. When Phillip Cage played, £21,000 was

split at a ratio of 2:5 between the arena and Phillip Cage. How much money did the arena make from Phillip Cage's concert?
Mathematics
1 answer:
natulia [17]3 years ago
5 0

Answer:

£6000

Step-by-step explanation:

Given:

Phillip Cage played, £21,000 was split at a ratio of 2:5 between the arena and Phillip Cage.

Question asked:

How much money did the arena make from Phillip Cage's concert?

Solution:

Ratio Arena and Philip cage in which money distributed = 2 : 5

Let ratio be x

Money earned by Arena = 2x

Money earned by Phillip Cage = 5x

Phillip Cage played total for =  £21,000

<u>Money earned by Arena + Money earned by Phillip Cage = £21,000</u>

2x+5x=21000\\7x=21000\\

Dividing both sides by 7

x=3000

Money earned by Arena = 2x = 2\times3000=6000

Thus, Arena made  £6000 from Phillip Cage's concert.

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Setler79 [48]
Answer: 180cm^2

Explanation: First, multiply 1.5 by 1.2 to get the area of the rectangle in METERS, which is 1.8. Since the question is asking for the area in CENTIMETERS, multiply 1.8 by 100 (because 1 meter=100 centimeters) to get 180cm^2.

Hope that helped :)
7 0
2 years ago
Consider the equation 360=__+84. Use the bar diagram to represent the equation. Then solve for the unknown value.
Andreyy89

Answer:

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Step-by-step explanation:

you would subtract 84 from 360 and then you have your answer!!

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3 years ago
|3x+6|+3=6<br> What is the answer?
GrogVix [38]

Answer:

x=-3 or x=-1

Step-by-step explanation:

Subtract 3 from both sides of your equation, it should look like this |3x+6|+3-3=6-3.

Simplify to get |3x+6|=3

Apply the absolute rule to get 3x+6=-3 or 3x+6=3.

3x+6=-3 : x=-3

3x+6=3 : x=-1

I'm glad I was able to help have a great day!

8 0
2 years ago
What is the greatest common factor of 10 and 4?
cluponka [151]

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Answer: GCF of 4 and 10 is 2.

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3 0
2 years ago
Read 2 more answers
HELP ASAP I WILL GIVE BRAINLIEST!!
Alexxx [7]

Consider the function F(x)= x³ +½x² −2x +3. Use calc and algebra to find any and all stationary points on the graph of the function.Precalc need help ASAP

Solution:

the above function has more than one root or more than one solution. The derivative of the function represents the slope of the tangent line to the curve

F(x)= x³ +½x² −2x +3, F'(x) = 3(x3-1)+(1/2)(2)(x2-1)-2(x1-1)+0

F'(x)=3x2+x-2 is the slope of the tangent line

setting the slope =0 and solving the quadratic equations, you find all the

critical points of interest

3x2+x-2=0, solve by factoring (3x-2)(x+1)=0, then 3x-2=0, x= 2/3

and x+1=0, x=-1 substituting these values of x in the original equation

you get the corresponding values of F(x) such that;

F(x)= x³ +½x² −2x +3, F(x)=(2/3)3+1/2(2/3)2-2(2/3)+3

= 8/27+4/18-4/3+3 = 8/27+2/9-4/3+3/1 = 59/27 and the first point is

(2/3, 59/27)

F(x)= x³ +½x² −2x +3, F(x)=(-1)3+1/2(-1)2-2(-1)+3

= -1+1/2+2+3 = 9/2 and the 2nd point is ( -1, 9/2)

these two points represents points where the slope of the tangent line to the curve is 0 and could be either maximum or minimum points

You can also find the y intercepts where x = 0 F(x)= x³ +½x² −2x +3, setting x = 0, y= F(x)=3 and the point ( 0,3) is a y intercept setting y = 0, then x intercepts can be found upon solving the equation x³ +½x² −2x +3 =0

3 0
2 years ago
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