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mihalych1998 [28]
3 years ago
11

Please Someone Help me!!

Mathematics
1 answer:
EastWind [94]3 years ago
3 0
(27 1/4) / (2 1/2) = 
(109/4) / (5/2) = 
109/4 * 2/5 = 
218/20 =
10.9....so there is 10 full 2 1/2 oz bags

each bag sells for 4.25.....so 10 bags would sell for 4.25(10) = 42.50
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PLEASE HELP ME FOR BRAINLIEST!!!!
lana [24]
Use cosine rule and sine rule
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Graph the image of this figure after a dilation with a scale factor of 1/3 centered at the origin.
posledela

Answer:

see attached diagram

Step-by-step explanation:

A dilation with a scale factor of \dfrac{1}{3} centered at the origin has a rule:

(x,y)\mapsto\left(\dfrac{x}{3},\dfrac{y}{3}\right).

Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates

  • D\left(\dfrac{-3}{3},\dfrac{3}{3}\right)\Rightarrow D(-1,1);
  • E\left(\dfrac{3}{3},\dfrac{9}{3}\right)\Rightarrow E(1,3);
  • F\left(\dfrac{6}{3},\dfrac{6}{3}\right)\Rightarrow F(2,2).

3 0
3 years ago
G(-5) = -4*|(-5)-1|
Mamont248 [21]
There is one answer, -24.

While yes, absolute value does indicate both a positive and negative will work, for every x value there will be only one y value associated with it; if there were more, then it would not meet the criteria to be a function.
7 0
3 years ago
What is 5 2/3 as a improper fraction
Sati [7]

17/3. 5 times 3 is 15. Add the 2 from the numerator to get 17/3

5 0
3 years ago
Read 2 more answers
Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

But c=0

\implies -6a=-9

\implies a=\frac{3}{2}

C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
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