Question

There is a simple method for constructing a magic square for any odd value of n:

Answer 1

Answer:

See Explaination

Explanation:

class MagicSquare():

def __init__(self,side):

self.side=side

self.two_dimension=[]

for row in range(1,side+1):

row_line=[]

for col in range(1,side+1):

row_line.append(0)

self.two_dimension.append(row_line)

def display(self):

row=0

col=int((self.side-1)/2)

for i in range(1,self.side**2+1):

self.two_dimension[row][col]=i

row-=1

col+=1

if row==-1:

row=self.side-1

if col==self.side:

col=0

if self.two_dimension[row][col]==0:

continue

else:

row+=1

if row==self.side:

row==0

for line in self.two_dimension:

for num in line:

print("{0:>3}".format(num),end=" ")

print()

def main():

for i in range(1,14,2):

square=MagicSquare(i)

square.display()

print("----------------------------------------------------")

if __name__ == '__main__':

main()