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S_A_V [24]
4 years ago
14

Can someone help me with this????

Mathematics
1 answer:
Irina-Kira [14]4 years ago
3 0
Angle 5= 46
Angle 7= 46  They are opposite, therefore, they measure the same.
 
If angle 2 is 134 degrees, so is angle 4.
They are parallel to each other, so angle 2 equals to angle 6, angle 4 equals to angle 8.
The sum of the four angles (5, 6, 7, & 8) is 360. The sum of the angle 2 (6) and angle 4 (8) is 268 (134x2).
360-268=92
92/2=46    Angles 5 and 7 are equal to each other, and their sum is 92, then you                    just need to divide 92 by two
                
               I do not know about the signs next to 5 and 7, though. I hope this helped                  you
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Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

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