Given that a<span>
local RadioShack store wants to buy a new line of plasma TVs.
Manufacturer A offers chain discounts of 18/12, and Manufacturer B
offers terms of 17/13.
Let the list price of the plasma TVs be x, then after a chain discount of 18/12 by Manufacturer A, the selling price of the plasma TVs will be (1 - 0.18)(1 - 0.12)x = 0.82(0.88)x = 0.7216x
Also, after the discount of 17/13 by manufacturer B, the selling price of the plasma TVs will be (1 - 0.17)(1 - 0.13)x = 0.83(0.87)x = 0.7221x
Thus, the final selling price after discount by manufacturer A is 0.7216 and the final selling price after dscount by manufacturer B is 0.7221x.
Therefore, Manufacturer A offers a </span><span>single equivalent discount rate that is the best deal.</span>
Answer:
The expression will be 
Step-by-step explanation:
We have given the expression 
We have to write this expression in kkxxnn form , here kk is real number and nn is integer
We know the property of exponent that when two function are multiplied thn their exponent are added
So
Here kk = 2 and nn = 15
Step-by-step explanation:
since we are required to find side |BC| and the value of side |AB| is given as 6.3 cm
hence we find the cosine of the given angle...
cos71 = adjacent ÷ hypotenuse
cos71 = |AB| ÷ |BC|
cos 71 = 6.3 ÷ |BC|
|BC| = 6.3 ÷ 0.325
|BC| = 19.4 cm
The answer is C. I hope this helps you.
9514 1404 393
Answer:
(a, b) = (-2, -1)
Step-by-step explanation:
The transpose of the given matrix is ...
![A^T=\left[\begin{array}{ccc}1&2&a\\2&1&2\\2&-2&b\end{array}\right]](https://tex.z-dn.net/?f=A%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%26a%5C%5C2%261%262%5C%5C2%26-2%26b%5Cend%7Barray%7D%5Cright%5D)
Then the [3,1] term of the product is ...
![(A\cdot A^T)_{31}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}1&2&2\end{array}\right]=a+2b+4](https://tex.z-dn.net/?f=%28A%5Ccdot%20A%5ET%29_%7B31%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%262%26b%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%262%5Cend%7Barray%7D%5Cright%5D%3Da%2B2b%2B4)
and the [3,2] term is ...
![(A\cdot A^T)_{32}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}2&1&-2\end{array}\right]=2a-2b+2](https://tex.z-dn.net/?f=%28A%5Ccdot%20A%5ET%29_%7B32%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%262%26b%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%26-2%5Cend%7Barray%7D%5Cright%5D%3D2a-2b%2B2)
Both of these terms in the product matrix are 0. We can solve the system of equations by adding these two terms:
(a +2b +4) +(2a -2b +2) = (0) +(0)
3a +6 = 0
a = -2
Substituting for 'a' in term [3,1] gives ...
-2 +2b +4 = 0
b = -1
The ordered pair (a, b) is (-2, -1).
