(GEOMETRY), please help meee
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Answer:
The given functions are
The sine function has a standard period of by definition. However, this might change if we use a factor as coefficient of the x-varible, but in this case we don't have that.
Therefore, the period of both trigonometric functions is .
Now, the images of each function is the y-variable set values that defines each function.
So, the function has an image defined by the set
. It's impotant to notice that the range of a standard function is [-1,1], however, in this case, the function was shifted 1 unit up and it was streched by a factor of 4, that's why the standard image changes to
.
About the second function , the image set is
, because the function was streched by a factor of 2.
Additionally, the image attached shows the graph of the given functions.
Question 1)
Given
Interest I = $18
Principle P = $200
t = 1.5 years
To determine
Interest rate r = ?
Using the formula
susbtituting I = 18, t = 1.5 and P = 200
or
r = 6% ∵ 0.06 × 100 = 6%
Therefore, we conclude that the interest rate required to accumulate simple interest of $18.00 from a principal of $200 over 1.5 years is 6% per year.
Question 2)
Given
Interest I = $60
Principle P = $750
Interest rate = 4% = 0.04
To determine
Time period t = ?
Using the formula to calculate the time period
years
Therefore, the time required to accumulate simple interest of $ 60.00
from a principal of $ 750 at an interest rate of 4% per year is 2 years.