Consider the following expanded powers of (a + b)n, where a + b is any binomial and n is a whole number. Look for patterns.
Each expansion is a polynomial. There are some patterns to be noted.
1. There is one more term than the power of the exponent, n. That is, there are terms in the expansion of (a + b)n.
2. In each term, the sum of the exponents is n, the power to which the binomial is raised.
3. The exponents of a start with n, the power of the binomial, and decrease to 0. The last term has no factor of a. The first term has no factor of b, so powers of b start with 0 and increase to n.
4. The coefficients start at 1 and increase through certain values about "half"-way and then decrease through these same values back to 1.
Answer:
three consecutive odd integers are.
Step-by-step explanation:
Let x be the first term of odd integer,
Therefore, the second consecutive odd integers = 
Similarly, the third consecutive odd integers = 
Given:
The sum of the first term and second term is 344.
first term + second term = 344
Here first term is x and second term is .
Therefore, the first odd integers is 171.
And the second consecutive odd integers = 
Similarly, the third consecutive odd integers = 
<h3>
Answer:</h3>
By <em>100 times</em>.
Step-by-step explanation:
Each time something is in Scientific Notation, to every power of 10 something is multiplied by, it grows by 10 times.
By knowing that, if both equations use the same starting number, you can minus the notation section from the larger value, to find the answer.
10^6 - 10^4 = 10^2 ---> 100 times.
Hope that helps, :)
Answer:
Give me a second, I just finished answering it, and trying to find a way to take a picture of it and send it to you.
Step-by-step explanation:
Answer:
Step-by-step explanation:
656 ≈660 and 106 ≈ 100
this means
660×100
=66000
⇒ 656×106 ≈ 66000
