Write an equation in standard form of the line that passes through (4,−1) and has the slope m=3.
1 answer:
Answer :
m = 3
Point = (4,-1)
x1 = 4
y1 = -1
Formula =
y - y1 = m (x-x1)
y - (-1) = 3 (x -4)
y + 1 = 3x -12
y - 3x + 1 + 12 = 0
y - 3x + 13 = 0
The line = y - 3x + 13 = 0 or -3x + y + 13 = 0
I'm sorry if I'm wrong.
Cmiiw
Good luck
Love from Indonesia
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