Answer:
Step-by-step explanation:
Given that Events D and E are independent, with P(D)- 0.6 and P(D and E) - 0.18.
P(D and E) = P(D)*P(E) (since independent)
Or P(E) = 0.3
Using this we find
P(Dor E) =
QNo2
Since lights are independent
P(Both) = P(A) *P(B) =0.22 where A I light on and B second light on
P(AB') = P(A) P(B') = 0.33
When we add we get P(A) = 0.55
P(B) =
the probability that the second light will be red when he reaches it
= P(B) = 0.60