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Setler [38]
3 years ago
5

Wha is the distance between (4,-2) and (-3,6)

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0
Treat it like a triangle with the points at either end of the hypotenuse. Then the horizontal leg has length 7, and the vertical leg 8.

Apply Pythagoras and find length is sqrt ( 7*7+8*8 )=10.63 (or sqrt (113) if you want to be exact )
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What is13/250 as a decimal
vredina [299]
13/250 as a decimal is 0.052
7 0
3 years ago
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Find the value of each angle mentioned above.​
nataly862011 [7]

Answer:

36°, 42°, 72°, 102°, 108°

Step-by-step explanation:

Angles at a point = 360°

Therefore:

(3x - 6) + x + 3x + 2x + (x + 6) = 360°

Open parthenogenesis

3x - 6 + x + 3x + 2x + x + 6 = 360

Add like terms

10x = 360

Divide both sides by 10

x = 36

✔️Value of each angle:

Plug in the value of x in each expression

x = 36°

3x - 6 = 3(36) - 6 = 102°

3x = 3(36) = 108°

x + 6 = 36 + 6 = 42°

2x = 2(36) = 72°

3 0
3 years ago
Find the equation of the axis of symmetry for the parabola y = x^2 + 5x.
viktelen [127]
Axis of symmetry =-b/2a
so subsitiute
a=1,b=5
-5/2
i believe thr axis of symmetry is at -2.5
6 0
4 years ago
Solve the equation. 8 – 2x = –8x + 14
goldenfox [79]

Answer:

x=1

Step-by-step explanation:

We are asked to solve the given equation: 8-2x=-8x+14.

To solve this equation we will combine like terms by moving all the terms containing x to the left hand side of equation and terms without x to right hand side of equation.

Let us add 8x to both sides of our equation.

8-2x+8x=-8x+8x+14

8-2x+8x=14

8+6x=14

Let us subtract 8 from both sides of our equation.

8-8+6x=14-8

6x=14-8

6x=6

Upon dividing both sides of our equation by 6 we will get,

\frac{6x}{6}=\frac{6}{6}

x=\frac{6}{6}

x=1

Therefore, the value of x equals 1 will satisfy our given equation.

8 0
3 years ago
Read 2 more answers
Does the equation x^2-6x+y^2-6y =-9 intersects the y-axis
BabaBlast [244]
Intersecting the y axis means x is o, so you plug x=0 in the equation and solve for y. if y has real solutions, then the answer is yes.
Let's find out:
0+y^2-6y=-9
y^2-6y+9=0
(y-3)(y-3)=0
y=3
3 is a real number, so yes, the equation intersects the y axis at (0,3)
8 0
3 years ago
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