Question

2 A pharmacist has a 13 % alcohol solution and another 18 % alcohol solution. How much of each must he use to make 50 grams of a 14 % alcohol solution

Answer 1

Therefore he took 40 gram of $1^{st}$ type solution and 10 gram of $2^{nd}$ type solution.

Step-by-step explanation:

Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .

Let he took x gram solution of $1^{st}$ type solution

and he took (50-x) gram of $2^{nd}$ type solution.

Total  amount of alcohol =$[x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]$ gram

Total amount of solution = 50 gram

According to problem

⇔$\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}$

⇔$\frac{13x +900-18x}{100\times50} =\frac{14}{100}$

⇔- 5x= 700 - 900

⇔5x = 200

⇔x = 40 gram

Therefore he took 40 gram of $1^{st}$ type solution and (50 -40)gram = 10 gram of $2^{nd}$ type solution.

Answer 2

Answer:

40 of first and 10 of second

Step-by-step explanation: