Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
Answer:
x= -2/3y-4
Step-by-step explanation:
3x+2y=-12
3x+2y-2y= -2y-12
3x=-2y-12
3x/3= -2y/3-12/3
x= -2/3y-4
It will be 5x3=15+23=38 so 38 pounds the puppy weigh
8x+6=62
Subtract 6 from both sides
8x= 56
Divide both sides by 8
x=7
Final answer: The number is 7
